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Question

If fx=0x=0x-3x>0, then the function fx is


A

increasing when x>0

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B

strictly increasing when x>0

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C

strictly increasing at x=0

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D

not continuous at x=0 and so it is not increasing when x>0

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Solution

The correct option is B

strictly increasing when x>0


Explanation for the correct option.

Find the nature of the given function.

For x>0 the function is defined as fx=x-3, now the derivative of the function is f'x=1.

So it can be seen that the function in the interval x>0 is such that f'x>0, so the function is strictly increasing in this interval.

The function fx is strictly increasing when x>0.

Hence, the correct option is B.


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