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Absolute Value Function

If fx=|x2-4 x...

Question

If $f (x) = | x^{2} - 4 x + 3 |,$ then

A

f (x) = x^{2} - 4 x + 3

when

x^{2} - 4 x + 3 \geq 0

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B

f (x) = x^{2} - 4 x + 3

when

x^{2} - 4 x + 3 \leq 0

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C

f (x) = - (x^{2} - 4 x + 3)

when

x^{2} - 4 x + 3 > 0

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D

f (x) = - (x^{2} - 4 x + 3)

when

x^{2} - 4 x + 3 < 0

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Solution

The correct options are
A $f (x) = x^{2} - 4 x + 3$ when $x^{2} - 4 x + 3 \geq 0$
D $f (x) = - (x^{2} - 4 x + 3)$ when $x^{2} - 4 x + 3 < 0$
$f (x) = {\begin{matrix} x^{2} - 4 x + 3, & x^{2} - 4 x + 3 \geq 0 - (x^{2} - 4 x + 3), & x^{2} - 4 x + 3 < 0 \end{matrix}$

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Similar questions

Find the domain of $f(x)=\sqrt (x2+4x−2x2−3)$f(x)=x2+4x−2x2−3

Question 10
Which of the following equations has no real roots?
(A) $x^{2} - 4 x + 3 \sqrt{2} = 0$
(B) $x^{2} + 4 x - 3 \sqrt{2} = 0$
(C) $x^{2} - 4 x - 3 \sqrt{2} = 0$
(D) $3 x^{2} - 4 \sqrt{3} x + 4 = 0$

f (x) = | x^{2} - 4 x + 3 |

f^{'} (x)

f (x) = \frac{x^{2} - 3 x + 1}{x^{2} + 4 x + 3},

f (x)

f (x) = x^{2} - 4 x + 3

, find value of F(2) - F(1)

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Absolute Value Function

Standard XII Mathematics

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