Question

If $f\left(x\right)=x^2,g\left(x\right)=x^2-5x+6$, then $g\left(2\right)+g\left(3\right)+g\left(0\right)-f\left(0\right)-f\left(1\right)-f(-2)$

• A. $2$
• B. $\frac{6}{5}$
• C. $\frac{5}{6}$
• D. $1$

Answer 1

Answer: (D)

$1$

$g\left(2\right)=g\left(3\right)=0;g\left(0\right)=6$
$f\left(0\right)=0;f\left(1\right)=1;f\left(2\right)=4$
$\Rightarrow 6-1-4=1$