Differentiation of Inverse Trigonometric Functions
If f x = x +t...
Question
If f(x) = x + tan x and f is inverse of g, then g’(x) is equal to
A
11+(g(x)−x)2
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B
11−(g(x)−x)2
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C
12+(g(x)−x)2
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D
12−(g(x)−x)2
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Solution
The correct option is C12+(g(x)−x)2 Let y=f(x)⇒x=f−1(y) then f(x) = x + tan x ⇒y=f−1(y)+tan(f−1(y)) ⇒ y = g(y) + tan(g(y)) or x = g(x) + tan(g(x)) . . .. (i) Differentiating both sides, then we get 1 = g’(x) + sec2 g(x) · g’(x) ∴g′(x)=11+sec2(g(x))=11+1+tan2(g(x)) =12+(x−g(x))2[fromEq.(i)] =12+(g(x)−x)2