If f(x) = x + x + tan x, and f is inverse of g, then g'(x) equal to
A
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B
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C
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D
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Solution
The correct option is C f(x)=x+tanxf(f−1(y))=f−1(y)+tan(f−1(y))y=g(y)+tan(g(y))x=g(x)+tan(g(x))differentiatew.r.tx1=g′(x)+sec2(g(x)).g′(x)g′(x)=12+[g(x)−x]2