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Question

If f(y)=1(y1)+(y1)2(y1)3+.....(y1)17 then the coefficient of y2 in it is?

A
17C3
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B
18C3
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C
17C2
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D
18C2
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Solution

The correct option is B 18C3
f(y)1=1(y1)+(y1)2(y1)3+..........(y1)17Then,Coefficientofy22C0y2+3C1y2+4C2y2+..........17C15y22C0+3C1+4C2+..........17C15[nCr=nCnr]2C0+3C2+4C2+5C2..........17C2

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