If f(y)=1−(y−1)+(y−1)2−(y−1)3+.....−(y−1)17 then the coefficient of y2 in it is?
A
17C3
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B
18C3
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C
17C2
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D
18C2
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Solution
The correct option is B18C3 f(y)1=1−(y−1)+(y−1)2−(y−1)3+..........(y−1)17Then,Coefficientofy2⇒2C0y2+3C1y2+4C2y2+..........17C15y2⇒2C0+3C1+4C2+..........17C15[∵nCr=nCn−r]⇒2C0+3C2+4C2+5C2..........17C2