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Question

If five G.M.′s are inserted between 486 and 23 then fourth G.M will be

A
4
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B
6
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C
12
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D
6
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Solution

The correct option is C 6
Let G1,G2,G3,G4,G5 be five G.M's
Then 486,G1,G2,G3,G4,G5,23 is a G.P with a=486 and a7=23
Now a7=23
ar6=23
486r6=23
r6=23×1486
r6=13×243
r6=136
r=±13
Now, G4=a5=ar4=486×(13)4=48681=6

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