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Question

If for non-zero x, 2 f(x)+3 f(1x)=1x5, then the value of f(2) is

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Solution

2 f(x)+3 f(1x)=1x5 .....[1]
Let f(x) = p and f(1x)=q[1]2p+3q=1x5.....(2]Substituting 1xin place of x in (1], we get :2 f(1x)+3 f(x)=x5or, 3p+2q=x5 ...(3]Solving (2]and (3] we get:p=15(2x3x+5]f(x)=15(2x3x+5]f(2)=15(223(2)+5]=15×0 = 0

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