If for positive integers r > 1 n > 1 and the coefficient of (3r)th and (r+2)th terms in the binomial expansion of (1+x)2n are equal, then
n=2r
T3r=2nC3r−1(x)3r−1
Tr+2=2nCr+1(x)r+1
It is given the coefficients are equal.
⇒20Cr+1=20C3r−1
⇒3r−1=r+1 or (3r−1)+(r+1)=2n
⇒r=1 or n=2r
But r > 1
⇒n=2r