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Quadratic Equations

If 1/3 and -1...

Question

If $\frac{1}{3}$ and - $\frac{1}{3}$ are the roots of equation $a x^{2} + b x + c = 0$ , then value of (a+b+c) is

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Solution

The correct option is A
8

Sum of roots = 0, therefore b = 0

Product of roots = - $\frac{1}{9}$

So, the equation will be $9 x^{2} - 1$ = 0

a + b + c = 8

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Similar questions

If the equation $x^{4} - 4 x^{3} + a x^{2} + b x + 1 = 0$ has four roots. All of them are positive real roots then value of a and b are given.

x^{2} + 2 x + 3 = 0

a x^{2} + b x + c = 0

ϵ

α

β

a x^{2} + b x + c = 0

l i m x \to a {[a x^{2} + b x + c + 1]}^{2 / (x - a)}

x_{1}

x_{2}

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x^{2} + 2 x + 3 = 0

a : b : c

1 : 2 : 3

x^{2} + 2 x + 3 = 0

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