If 2-9 of a property costs Rs- 2-52-000- find the cost of 4-7 of it-

2/9 of a property costs = Rs. 252000 1 of a property costs =Rs. 252000 ×9/2 =Rs. 2268000/2 =Rs. 1134000 4/7 of a property costs =1134000 ×4/7 =162000 × 4 =Rs. 6 ...

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Standard VIII

Mathematics

Relation for Direct Proportion

If 2/9 of a p...

Question

If $\frac{2}{9}$ of a property costs Rs. 2,52,000; find the cost of $\frac{4}{7}$ of it.

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Solution

$\frac{2}{9}$ of a property costs = Rs. 252000
1 of a property costs $= R s . 252000 \times \frac{9}{2}$
$= R s . \frac{2268000}{2}$
$= R s . 1134000$
$\frac{4}{7}$ of a property costs $= 1134000 \times \frac{4}{7}$
$= 162000 \times 4$
$= R s . 648000$

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If 29 of a property costs Rs. 2,52,000; find the cost of 47 of it.

29 of a property costs = Rs. 252000 1 of a property costs =Rs.252000×92 =Rs.22680002 =Rs.1134000 47 of a property costs =1134000×47 =162000×4 =Rs.648000

If $\frac{2}{9}$ of a property costs Rs. 2,52,000; find the cost of $\frac{4}{7}$ of it.

$\frac{2}{9}$ of a property costs = Rs. 252000
1 of a property costs $= R s . 252000 \times \frac{9}{2}$
$= R s . \frac{2268000}{2}$
$= R s . 1134000$
$\frac{4}{7}$ of a property costs $= 1134000 \times \frac{4}{7}$
$= 162000 \times 4$
$= R s . 648000$