Question

If $\frac{3}{5}$ of a number exceeds it's $\frac{2}{7}$ by $44$. Find the number.

Answer 1

Let the number be $x$.
It is given that, If $\frac{3}{5}$ of a number exceeds it's $\frac{2}{7}$ by $44$.

$\Rightarrow \frac{3}{5}x=\frac{2}{7}x+44$
$\Rightarrow \frac{3}{5}x-\frac{2}{7}x=44$
$\Rightarrow \frac{21x-10x}{35}=44$

$\Rightarrow 11x=35\times 44$
$\Rightarrow 11x=1540$
$\Rightarrow x=\frac{1540}{11}$
$\Rightarrow x=140$

Therefore, the required number is $140$.