Question

If $\frac{a}{b}$ = $\frac{16}{3}$

then find the value of $\frac{a+b}{a-b}$

• A. $\frac{9}{13}$
• B. $\frac{19}{13}$
• C. $\frac{13}{19}$
• D. $\frac{16}{13}$

Answer 1

The correct option is B

$\frac{19}{13}$

Given $\frac{a}{b}$ = $\frac{16}{3}$

we know if $\frac{a}{b}$ = $\frac{c}{d}$

then $\frac{a+b}{a-b}$ = $\frac{c+d}{c-d}$

Hence $\frac{a+b}{a-b}$ =$\frac{16+3}{16-3}$

= $\frac{19}{13}$