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Question

If d2xdy2(dydx)3+d2ydx2=k, then k is equal to

A
1
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B
2
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C
None of these
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Solution

dydx=(dxdy)1d2ydx2=(dxdy)2{ddx(dxdy)}d2ydx2=(dxdy)2{ddy(dxdy)dydx}d2ydx2=(dydx)2{d2xdy2.dydx}d2ydx2=(dydx)3d2xdy2d2ydx2+(dydx)3d2xdy2=0

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