If d-d x-1-x2-x4-1-x-x2-a x-b then a- b-

The correct option is D (2, 1) 1+x^2+x^4=(1+x+x^2)(+ x+x^2) d/dx(1 x+x^2)= 2x 1=ax+b ...

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Binomial Theorem

If d/d x[1+x2...

Question

$I f \frac{d}{d x} [\frac{1 + x^{2} + x^{4}}{1 + x + x^{2}}] = a x + b t h e n (a, b) =$

(1, 2)

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(-2, 1)

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(2, -1)

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(1, 2)

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Solution

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Similar questions

(\frac{1 + x^{2} + x^{4}}{1 + x + x^{2}}) = a x + b

: (a, b) \equiv

\frac{d}{d x} (\frac{1 + x^{2} + x^{4}}{1 + x + x^{2}}) = a x + b

=

\frac{1}{x^{4} + x^{2} + 1} = \frac{A x + B}{x^{2} + x + 1} + \frac{C x + D}{x^{2} - x + 1}

C + D =

\frac{d}{d x} (\frac{1 + x^{2} + x^{4}}{1 + x + x^{2}}) = a x + b

(a, b) =

\frac{d}{d x} (\frac{1 + x^{2} + x^{4}}{1 + x + x^{2}}) = A x + B

B

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