If p - q - x -3- x -3- then what is the value of p 2- q 2- p 2- q 2 -A- x2-9-3 x-B- x2-18-x2- 0C- x2-9-x2-18D- x2-18-6 x

The correct option is C x^2+9/6xp^2 q^2 = (x+3)^2+(x 3)^2 = 2x^2 + 18 p^2 q^2 = (x + 3)^2 nbsp;(x 3)^2 = 12x p^2+q^2/p^2 q^2 = 2x^2+18/12x=x^2+9/6x ...

You visited us 1 times! Enjoying our articles? Unlock Full Access!

Byju's Answer

Standard IX

Mathematics

Long Division Method to Divide Two Polynomials

If p / q = x ...

Question

If $\frac{p}{q} = \frac{x + 3}{x - 3^{'}}$ then what is the value of $\frac{p^{2} + q^{2}}{p^{2} - q^{2}} ?$

\frac{x^{2} + 9}{3 x}

No worries! We‘ve got your back. Try BYJU‘S free classes today!

\frac{x^{2} + 18}{6 x}

No worries! We‘ve got your back. Try BYJU‘S free classes today!

\frac{x^{2} + 9}{6 x}

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

\frac{x^{2} + 18}{6 x}

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Open in App

Solution

The correct option is C $\frac{x^{2} + 9}{6 x}$
$p^{2} - q^{2} = (x + 3)^{2} + (x - 3)^{2} = 2 x^{2} + 18$
$p^{2} - q^{2}$ = (x + 3) $^{2}$ - (x - 3) $^{2}$ = 12x
$\frac{p^{2} + q^{2}}{p^{2} - q^{2}} = \frac{2 x^{2} + 18}{12 x} = \frac{x^{2} + 9}{6 x}$

Suggest Corrections

Similar questions

Q. Find the value of

x

x^{2} + p^{2} = (q - x)^{2}

Q. The value of

x

satisfying the equation

x^{2} + p^{2} = (q - x)^{2}

Q. If

f (x) = \sqrt{x^{2} + 6 x + 9} - \sqrt{x^{2} - 6 x + 9}

, then the value of

f (\frac{456}{123}) - f (- \frac{456}{123})

Q. If 2 divides

x^{2} + 6 x + 9

then

x + 3

would be a/an
for any value of

x

,
provided

x^{2} + 6 x + 9

is a positive integer.

Q. If the solution of the equation

∣ ∣ (x^{4} - 9) - (x^{2} + 3) ∣ ∣ = ∣ ∣ x^{4} - 9 ∣ ∣ - ∣ ∣ x^{2} + 3 ∣ ∣

(- \infty, p] \cup [q, \infty)

, then the value of

p + q

Join BYJU'S Learning Program

If pq=x+3x−3′ then what is the value of p2+q2p2−q2?

The correct option is C x2+96xp2−q2=(x+3)2+(x−3)2=2x2+18 p2−q2 = (x + 3)2 - (x - 3)2 = 12x p2+q2p2−q2=2x2+1812x=x2+96x

If $\frac{p}{q} = \frac{x + 3}{x - 3^{'}}$ then what is the value of $\frac{p^{2} + q^{2}}{p^{2} - q^{2}} ?$

The correct option is C $\frac{x^{2} + 9}{6 x}$
$p^{2} - q^{2} = (x + 3)^{2} + (x - 3)^{2} = 2 x^{2} + 18$
$p^{2} - q^{2}$ = (x + 3) $^{2}$ - (x - 3) $^{2}$ = 12x
$\frac{p^{2} + q^{2}}{p^{2} - q^{2}} = \frac{2 x^{2} + 18}{12 x} = \frac{x^{2} + 9}{6 x}$