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Question

If from a point P(a,b,c) perpendiculars PA,PB are drawn to yz and zx planes, then the equation of the plane OAB is

A
bcx+cay+abz=0
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B
bcx+cayabz=0
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C
bcxcay+abz=0
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D
bcx+cay+abz=0
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Solution

The correct option is B bcx+cayabz=0
A[0,b,c] in yz - plane
B[a,0,c] in zx - plane.
Plane through O is px+qy+rz=0.
It passes through A and B.
0p+qb+rc=0 and pa+0b+rc=0
pbc=qca=rab.
Hence the plane is as in ( b ).

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