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Standard XII

Physics

Principle of Superposition

If g on the...

Question

If $g$ on the surface of the earth is $9.8 / m s^{- 2}$ , its value at a depth of $3200 k m$ (Radius of the earth= $6400 k m$ ) is

9.8 / m s^{- 2}

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Zero

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4.9 / m s^{- 2}

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2.45 / m s^{- 2}

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Solution

The correct option is C $4.9 / m s^{- 2}$ ,
$g_{d} = g (1 - \frac{d}{R})$
$⟹ 9.8 (1 - \frac{3200 \times 10^{3}}{6400 \times 10^{3}})$
$4.9 m / s^{2}$

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Similar questions

Q. If

g

on the surface of the Earth is

9.8 m s^{- 2}

, its value at a height of

6400 k m

is: (Radius of the Earth

= 6400 k m

)

Q. The value of

g

at a particular point on the earth surface is

9.8 m s^{- 2}

. Suppose the earth suddenly shrinks uniformly to half its present size without losing any mass. The value of ‘g’ at the same point (assuming that the distance of the point from the centre of earth does not shrink) will now be:

Q. If mass and radius of the Earth are

6.0 \times 10^{24} k g

and

6.4 \times 10^{6} m

respectively. Calculate the force exerted by the Earth on a body of mass 1 kg, acceleration of the body of mass 1 kg and acceleration of the Earth in order.
Use

G = 6.67 \times 10^{- 11} N m^{2} k g^{- 2}

Q. If the mass of a body is

5 k g

, its weight on the surface of Earth would be: (Take

g = 9.8 m s^{- 2}

)

A body weighs 100 N on the surface of Earth. What will be the acceleration due to gravity acting on the body at a height of 3400 km above Earth's surface? Taking the mass of Earth $= 6 \times 10^{24} k g$ , Radius of earth $= 6.4 \times 10^{6} m$ and $G = 6.7 \times 10^{- 11} N m^{2} k g^{- 2}$ .

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If g on the surface of the earth is 9.8/ms−2, its value at a depth of 3200 km (Radius of the earth=6400 km) is

The correct option is C 4.9/ms−2,gd=g(1−dR)⟹9.8(1−3200×1036400×103)4.9m/s2

If $g$ on the surface of the earth is $9.8 / m s^{- 2}$ , its value at a depth of $3200 k m$ (Radius of the earth= $6400 k m$ ) is

The correct option is C $4.9 / m s^{- 2}$ ,
$g_{d} = g (1 - \frac{d}{R})$
$⟹ 9.8 (1 - \frac{3200 \times 10^{3}}{6400 \times 10^{3}})$
$4.9 m / s^{2}$