Question

If $H^{+}$ ion concentration in water is ${10}^{-2}$ mol/l then $O{H}^{-}$ ion concentration

• A. $17\times {10}^{-3}$
• B. 17
• C. $17\times {10}^{-2}$
• D. $17\times {10}^{-1}$

Answer 1

The correct option is A $17\times {10}^{-3}$

$\text{Concentration of}{H}^{+}={10}^{-2}$
$\text{Concentration of}{H}^{+}+\text{Concentration of}O{H}^{-}={10}^{-14}$

$O{H}_{\left(mg/l\right)}^{-}={10}^{-12}\times 17\times 1000\times {10}^6$

$=17\times {10}^{-3}$