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Question

If ^i+^k and 2^i+^j+^k are two vectors inclined at an angle π3, then the value of |a+b| is.

A
Grater than 1
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B
Less than 1
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C
Equal to 1
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D
Equal to 0
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Solution

The correct option is D Grater than 1
Given:a=i+k and b=2i+j+k. \
Therefore their sum will be a+b=3i+j+2k
Hence, |a+b|=32+12+22 =14
Thus the |a+b| is greater than 1

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