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Question

If heat of dissociation of CHCl2COOH is 0.7 kcal/mole then ΔH for the reaction:

CHCl2COOH + KOH CHCl2COOK + H2O


A

-13 kcal

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B

+13 kcal

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C

-14.4 kcal

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D

-13.7 kcal

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Solution

The correct option is A

-13 kcal


H+ + OH H2O(l)

ΔH = 13.7 kcal........(i)

CHCl2COOH CHCl2COO + H+

ΔH = 0.7 kcal........(ii)

CHCl2COOH + OH CHCl2COO + H2O(l)

ΔH = ?

Adding equation (i) and (ii) ΔH = = 13Kcal.


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