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Van't Hoff Factor

If Hg2Cl2 is ...

Question

If $H g_{2} C l_{2}$ is 80% ionised in the aqueous solution what will be the van't Hoff factor of $H g_{2} C l_{2}$ in the solution?

A

1.6

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B

2.6

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C

3.6

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D

4.6

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Solution

The correct option is B 2.6
$H g_{2} C l_{2} (a q) ⇌ H g_{2}^{2 +} + 2 C l^{-} I n i t i a l l y : C 00 E q b : C - C α C α 2 C α$

$i = \frac{No. of moles after dissociation}{No. of moles before dissociation}$

$i = \frac{C - C α + C α + 2 C α}{C} i = \frac{C + 2 C α}{C} = 1 + 2 α$
Given that :
$α = 0.8$
$i = 1 + (2 \times 0.8) i = 2.6$

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Van't Hoff Factor

Standard XII Chemistry

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