Question

If $I_0$ is the intensity of principal maximum in the single slit diffraction experiment, the intensity of the principal maximum when the slit width is doubled is

• A. $2I_0$
• B. $4I_0$
• C. $I_0$
• D. $\frac{I_0}{2}$

Answer 1

The correct option is (B) $I_0$

$intensityatapointcanbegivenbe$

$I=I_0{\left(\frac{\sin \theta }{\theta }\right)}^2$

$widthformula$

$\theta =\left(\frac{\pi ay}{\lambda D}\right);$

$puty=0,\theta =0$

${\left(\frac{\sin \theta }{\theta }\right)}^2⟶1$

$I=I_0$

The principal maximum in diffraction is independent of the width of the slit