Question

In young's double slit experiment the maximum intensity is $I_0$. When one slit is closed , the intensity becomes:

• A. $\frac{I_0}{2}$
• B. $\frac{I_0}{8}$
• C. $\frac{I_0}{4}$
• D. $I_0$

Answer 1

The correct option is C $\frac{I_0}{4}$

In young's double slit experiment, maximum central intensity is given by

$I_0=(\sqrt{I_1}+\sqrt{I_2}{)}^2$

If $I_1=I_2=I\left(say\right)$

$I_0=(\sqrt{I}+\sqrt{I}{)}^2=(2\sqrt{I}{)}^2$

$I_0=4I$

$I=\frac{I_0}{4}$ Intensity of the source

When one slit is closed, then no interference pattern will be formed and the intensity at the center is $\left(I_0/4\right)$

The correct option is C.