If in the circuit- power dissipation is 150 W then R isA- 4 -B- 2 - 6 -D- 5 -

The correct option is C 6 ΩP = v^2/R_eff ∴ 150 = (15)^2/(2R/R + 2)∴2R/R + 2 = 1̸5̸^̸3̸ ̸×̸1̸̸̸5̸̸̸/1̸5̸0̸ 1̸0̸_̸2̸⇒ R = 6 Ω ...

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Byju's Answer

Standard XII

Physics

Power Delivered and Heat Dissipated in a Circuit

If in the cir...

Question

If in the circuit, power dissipation is 150W then R is

2 Ω

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6 Ω

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5 Ω

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4 Ω

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Solution

The correct option is B $6 Ω$
$P = \frac{v^{2}}{R_{e f f}} ∴ 150 = \frac{(15)^{2}}{(\frac{2 R}{R + 2})} ∴ \frac{2 R}{R + 2} = \frac{/ 15^{3} \times / 15}{/ 150 / 10_{2}} \Rightarrow R = 6 Ω$

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If in the circuit, power dissipation is 150W then R is

The correct option is B 6ΩP=v2Reff∴150=(15)2(2RR+2)∴2RR+2=/153×/15/150 /102⇒R=6Ω

The correct option is B $6 Ω$
$P = \frac{v^{2}}{R_{e f f}} ∴ 150 = \frac{(15)^{2}}{(\frac{2 R}{R + 2})} ∴ \frac{2 R}{R + 2} = \frac{/ 15^{3} \times / 15}{/ 150 / 10_{2}} \Rightarrow R = 6 Ω$