If in the given figure i -0-25 amp- then the value R will beA- 48 -B- 12 -C- 120 -D- 42 -

The correct option is D 42 Ωi = 0.25 amp V = 12 V R_eq = V/i = 12/0.25 = 48 Ω Now from the circuit R_eq = R + (60 ∥ 20 ∥ 10) ⇒ R = R_eq 6 = 48 6 = 42 Ω ...

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Standard XII

Physics

Simple Circuit

If in the giv...

Question

If in the given figure i = 0.25 amp, then the value R will be

48 Ω

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12 Ω

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120 Ω

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42 Ω

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Solution

The correct option is D $42 Ω$
i = 0.25 amp V = 12 V
$R_{e q} = \frac{V}{i} = \frac{12}{0.25} = 48 Ω$
Now from the circuit $R_{e q} = R + (60 ∥ 20 ∥ 10)$

$\Rightarrow R = R_{e q} - 6 = 48 - 6 = 42 Ω$

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If in the given figure i = 0.25 amp, then the value R will be

The correct option is D 42Ωi = 0.25 amp V = 12 V Req=Vi=120.25=48Ω Now from the circuit Req=R+(60∥20∥10) ⇒R=Req−6=48−6=42Ω

The correct option is D $42 Ω$
i = 0.25 amp V = 12 V
$R_{e q} = \frac{V}{i} = \frac{12}{0.25} = 48 Ω$
Now from the circuit $R_{e q} = R + (60 ∥ 20 ∥ 10)$

$\Rightarrow R = R_{e q} - 6 = 48 - 6 = 42 Ω$