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Question

If |z3i|5 then the minimum value of |z+2| will be

A
0
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B
2
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C
513
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D
1
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Solution

The correct option is A 0
|z3i|5(x)2+(y3)225
Putting y=0,
x2+9=25x=±4


The minimum of |z+2| will occur at z=2 and the minimum value is 0

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