If instead of given amount of sodium thiosulphate, 2 moles of sodium thiosulphate along with 3 moles of $C u S O_{4}$ were taken initially. Then moles of sodium cuprothiosulphate formed is :

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1.5

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Solution

The correct option is A 0
2 moles of sodium thiosulphate will completely react with 2 moles of $C u S O_{4}$ .
Thus, there is no sodium thiosulphate left to react in the second step. Hence, the reaction will stop at first step.
Then moles of sodium cuprothiosulphate formed is zero.

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The density of 3 molal sodium thiosulphate solution is $1.25 g / c m^{3}$ . The mole fraction of sodium thiosulphate is

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