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Concentration Terms

The density o...

Question

The density of $3$ M solution of sodium thiosulphate $(N a_{2} S_{2} O_{3})$ is $1.58$ g/ml., Calculate mole fraction of $N a_{2} S_{2} O_{3}$ .

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Solution

$Here,Molarityis3MDensity(d)is1.589gmlHeresoluteisNa2S2O3MolecularMassofsolute(Ma)=1589SolventisH2OM.Mofsolvent(Mb)=189weknowMolarity=XBd×1000XAMA+XBMB3=(1−xA)×1.58×1000xA(158)+(1−xA)(18)474xA+54−54xA=1580−1580xA2000xA=1526xA=15262000=0.763Molefractionis0.763$

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Similar questions

3

(N a_{2} S_{2} O_{3})

1.58

N a^{+}

S_{2} O_{3}^{2 -}

N a_{2} S_{2} O_{3}

1.25

^{- 1}

N a_{2} S_{2} O_{3}

(N a_{2} S_{2} O_{3})

1.25 g / m L

N a^{+}

S_{2} O_{3}^{2 -}

(N a_{2} S_{2} O_{3})

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(N a_{2} S_{2} O_{3})

1.2 g/mL

3 M

(N a_{2} S_{2} O_{3})

1.25 g m / m l

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