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Question

If dxx1x3=aln(1x3+b1x3+1)+k, then

A
b=1,a=1
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B
b=1,a=13
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C
b=1,a=23
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D
None of these
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Solution

The correct option is B b=1,a=13
I=dxx1x3Put 1x3=t23x2dx=2tdtI=23dt(1t2)=13(11t+11+t)dt.=13 log 1+t1t+c=13 log 1+1x311x3+c.

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