If ∫sec2x−2010sin2010xdx=f(x)sin2010x+c, then f(π3)= is
If ∫sec2x−2010sin2010x dx = f(x)sin2010x + c, then f (π3) =
If f(θ)=sin2θ+sin2(θ+2π3)+sin2(θ+4π3), then f(π15)
If f(x)+2f(1−x)=x2+1 ∀ xϵR then f(x) is