If intensity of radiation incident on a photocell be increased four times keeping frequency constant, then number of photoelectrons and energy of photoelectrons emitted become
A
Four times, doubled
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B
Doubled, remains unchanged
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C
Remains unchanged, doubled
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D
Four times, remains unchanged
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Solution
The correct option is B Four times, remains unchanged Number of photoelectrons emitted ∝ Intensity of radiation energy of photoelectrons
Energy of photoelectrons emitted ∝ Frequency
So, number of photoelectrons emitted becomes four times but energy of photoelectrons remains same.