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If K1 and ...

Question

If $K_{1}$ and $K_{2}$ are the respective equilibrium constants for the two reactions:
$X e F_{6} (g) + H_{2} O (g) \Leftrightarrow X e O F_{4} (g) + 2 H F (g)$
$X e O_{4} (g) + X e F_{6} (g) \Leftrightarrow X e O F_{4} (g) + X e O_{3} F_{2} (g)$
The equilibrium constant of the reaction $X e O_{4} (g) + 2 H F (g) \Leftrightarrow X e O_{3} F_{2} (g) + H_{2} O (g)$ will be:

A

K_{1} \times K_{2}

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B

\frac{K_{2}}{K_{1}}

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C

\frac{K_{1}}{(K_{2})^{2}}

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D

\frac{K_{1}}{K_{2}}

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Solution

The correct option is C $\frac{K_{2}}{K_{1}}$
First reaction is reversed and added to the second reaction to obtain the third reaction.
Hence, the equilibrium constant for the third reaction is the ratio of the equilibrium constants of second and first reaction.
Thus, $K = \frac{K_{2}}{K_{1}}$ .
$K_{1} = \frac{[X e O F_{4}] [H F]^{2}}{[X e F_{6}] [H_{2} O]}$
$K_{2} = \frac{[X e O F_{4}] [X e O_{3} F_{2}]}{[X e O_{4}] [X e F_{6}]}$
$K = \frac{[X e O_{3} F_{2}] [H_{2} O]}{[X e O_{4}] [H F]^{2}} = \frac{K_{2}}{K_{1}}$ .

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Similar questions

K_{1}

K_{2}

are the respective equilibrium constant for the reactions:
(i)

X e F_{6 (g)} + H_{2} O_{(g)} ⇌ X e O F_{4 (g)} + 2 H F_{(g)}; K_{1}

X e O_{4 (g)} + X e F_{6 (g)} ⇌ X e O F_{4 (g)} + X e O_{1} F_{2}; K_{2}

The equilibrium constant for the reaction

X e O_{4 (g)} + 2 H F_{(g)} ⇌ X e O_{3} F_{2 (g)} + H_{2} O_{(g)}

K_{1}

K_{2}

are the respective equilibrium constants for the two reactions

X e F_{6} (g) + H_{2} O (g) ⇌ X e O F_{4} (g) + 2 H F (g)

X e O_{4} (g) + X e F_{6} (g) ⇌ X e O F_{4} (g) + X e O_{3} F_{2} (g)

the equilibrium constant of the following reaction is:

X e O_{4} (g) + 2 H F (g) ⇌ X e O_{3} F_{2} (g) + H_{2} O (g)

K_{1}

K_{2}

are the respective equilibrium constants for the two reactions:
(i)

X e F_{6} (g) + H_{2} O (g) ⇌ X e O F_{4} (g) + 2 H F (g)

X e O_{4} (g) + X e F_{6} (g) ⇌ X e O F_{4} (g) + X e O_{3} F_{2} (g)

then the equilibrium constant for the reaction:

X e O_{4} (g) + 2 H F (g) ⇌ X e O_{3} F_{2} (g) + H_{2} O (g)

Q. Consider the two reactions:

X e F_{6} (g) + H_{2} O (g) ⇌ X e O F_{4} (g) + 2 H F (g); K_{1}

X e O_{4} (g) + X e F_{6} (g) ⇌ X e O F_{4} (g) + X e O_{3} F_{2} (g); K_{2}

Then, the equilibrium constant for the following reaction will be:

X e O_{4} (g) + + 2 H F (g) ⇌ X e O_{3} F_{2} (g) + H_{2} O (g)

Q. The equilibrium constants of the reactions

S O_{2} (g) + \frac{1}{2} O_{2} (g) ⇋ S O_{3} (g)

2 S O_{2} (g) + O_{2} (g) ⇋ 2 S O_{3} (g)

K_{1}

K_{2}

The relationship between

K_{1}

K_{2}

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