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Question

If k+2,4k6,3k2 are the three consecutive terms of an A.P., then the value of k is

A
2
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B
3
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C
4
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D
5
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Solution

The correct option is D 3
It is given that k+2,4k6,3k2 are the consecutive terms of A.P, therefore, by arithmetic mean property we have, first term+third term is equal to twice of second term that is:

(k+2)+(3k2)=2(4k6)4k=8k124k8k=124k=124k=12k=124=3

Hence k=3.

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