If k+2,4k−6,3k−2 are the three consecutive terms of an A.P., then the value of k is
A
2
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B
3
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C
4
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D
5
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Solution
The correct option is D3 It is given that k+2,4k−6,3k−2 are the consecutive terms of A.P, therefore, by arithmetic mean property we have, first term+third term is equal to twice of second term that is: