If k, (2k- 1) and (2k + 1) are the three successive terms of an AP, find the value of k.
If a,b, c are in Ap
b−a=c−b-----(1)
According to the given problem
a=k,b=2k−1,c=2k+1
Using (1)
(2k−1)−k=(2k+1)−(2k−1)
2k−1−k=2k+1−2k+1
k−1=2
k=2+1
k=3