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Question

if k, 2k-1 and 2k+1 are three consecutive terms of an AP, the value of k is?

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Solution

Let t1 = k; t2 = 2k-1; t3 = 2k+1Since, t1, t2 and t3 are in AP, then t2 - t1 = t3 - t22k-1-k = 2k+1-2k+1k-1 = 2k = 3

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