If k - p - q - r- then the value of k - r p q r k - p q r p k - q is -

The correct option is B 2k^3 Given, k=p+q+r We need to find value of k + r #160; amp; p amp; q r #160; amp; k + p #160; amp; ...

You visited us 1 times! Enjoying our articles? Unlock Full Access!

Properties of Determinants

If k = p + ...

Question

If $k = p + q + r$ , then the value of $∣ ∣ ∣ ∣ \begin{matrix} k + r & p & q r & k + p & q r & p & k + q \end{matrix} ∣ ∣ ∣ ∣$ is _____.

2 k^{2}

No worries! We‘ve got your back. Try BYJU‘S free classes today!

2 k^{3}

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

k^{3}

No worries! We‘ve got your back. Try BYJU‘S free classes today!

3 k^{2}

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Open in App

Solution

Suggest Corrections

Similar questions

\infty \sum k = 1 \frac{3 k^{2} + 3 k + 1}{(k^{2} + k)^{3}}

p^i +^j +^k,^i + q^j +^k

^i +^j + r^k

(p \neq q \neq r \neq 1)

p q r - (p + q + r)

k = p + q + r

∣ ∣ ∣ ∣ \begin{matrix} k + r & p & q r & k + p & q r & p & k + q \end{matrix} ∣ ∣ ∣ ∣

p^i +^j +^k,^i + q^j +^k

^i +^j + r^k (p \neq q \neq r \neq 1)

p q r - (p + q + r)

f (x) = x^{2} - p x + q

x = 2 k^{2}

q + 4 (q^{2}) + 6 p q =

Join BYJU'S Learning Program