wiz-icon
MyQuestionIcon
MyQuestionIcon
1
You visited us 1 times! Enjoying our articles? Unlock Full Access!
Question

If kinetic energy of a body is increased by 300%, then percentage change in momentum will be

A
100%
No worries! We‘ve got your back. Try BYJU‘S free classes today!
B
150%
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
C
265%
No worries! We‘ve got your back. Try BYJU‘S free classes today!
D
73.2%
No worries! We‘ve got your back. Try BYJU‘S free classes today!
Open in App
Solution

The correct option is B 150%
KE=12mv2=12m2v2m (momentum,p=mv)=12p2m
so, p=2(KE)m
Δpp=12ΔKEKE

given, ΔKEKE×100=300 %= 3
ΔKEKE=3
Therefore, ΔPP=12×3=1.5
ΔPP×100=150 %

flag
Suggest Corrections
thumbs-up
0
Join BYJU'S Learning Program
similar_icon
Related Videos
thumbnail
lock
Kinetic Energy and Work Energy Theorem
PHYSICS
Watch in App
Join BYJU'S Learning Program
CrossIcon