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Byju's Answer
Standard XIII
Physics
Defining Kinetic Energy
If kinetic en...
Question
If kinetic energy of a body is increased by 300%, then percentage change in momentum will be
A
100
%
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B
150
%
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C
265
%
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D
73.2
%
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Solution
The correct option is
B
150
%
K
E
=
1
2
m
v
2
=
1
2
m
2
v
2
m
(
∵
momentum
,
p
=
m
v
)
=
1
2
p
2
m
so,
p
=
√
2
(
K
E
)
m
⇒
Δ
p
p
=
1
2
Δ
K
E
K
E
given,
Δ
K
E
K
E
×
100
=
300
%=
3
Δ
K
E
K
E
=
3
Therefore,
Δ
P
P
=
1
2
×
3
=
1.5
⇒
Δ
P
P
×
100
=
150
%
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