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Question

If l1,m1,n1 and 12,m2,n2 are the direction cosines of two lines, then (l1l2+m1m2+n1n2)2+(m1n2m2n1)2=

A
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B
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C
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D
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Solution

The correct option is C 1
Dot product of dc's of two lines gives,
(l1^i+m1^j+n1^k).(l2^i+m2^j+n2^k)=l12+m12+n12×l22+m22+n22×cosθ
We know l12+m12+n12=1,l22+m22+n22=1
l1l2+m1m2+n1n2=1.1.cosθ(l1l2+m1m2+n1n2)2=cos2θ
Cross product of dc's of two lines
(l1^i+m1^j+n1^k)×(l2^i+m2^j+n2^k)=l12+m12+n12×l22+m22+n22×sinθ
Σ(m1n2m2n1)2=sinθΣ(m1n2m2n1)2=sin2θ
(l1l2+m1m2+n1n2)2+Σ(m1n2m2n1)2=cos2θ+sin2θ=1

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