If $l, b$ and $h$ of a cuboid are increased, decreased and increased by $1 %, 3 %$ and $2 %$ respectively, then the volume of the cuboid:

Increases

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Decreases

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Increases or decreases depending on original dimentions

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can't be calculated with given data

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Solution

The correct option is B Decreases
Volume of cuboid $= l \times b \times h$
Increased length $= \frac{101 l}{100}$
decreased width $= \frac{97 b}{100}$
Increased height $= \frac{102 h}{100}$
Volume of the resultant solid $= \frac{101 l}{100} \times \frac{97 b}{100} \times \frac{102 h}{100} = 0.9992 l b h$
Hence, the volume of resultant solid is decreased.

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If l,b and h of a cuboid are increased, decreased and increased by 1%,3% and 2% respectively, then the volume of the cuboid:

The correct option is B DecreasesVolume of cuboid =l×b×hIncreased length =101l100decreased width =97b100Increased height =102h100Volume of the resultant solid =101l100×97b100×102h100=0.9992lbhHence, the volume of resultant solid is decreased.

If $l, b$ and $h$ of a cuboid are increased, decreased and increased by $1 %, 3 %$ and $2 %$ respectively, then the volume of the cuboid: