1
You visited us
1
times! Enjoying our articles?
Unlock Full Access!
Byju's Answer
Standard XI
Mathematics
Standard Logarithm
If L= lim n →...
Question
If
L
=
lim
n
→
∞
(
n
+
2
)
!
+
(
n
+
1
)
!
(
n
+
2
)
!
−
(
n
+
1
)
!
then
10
L
is equal to
Open in App
Solution
L
=
lim
n
→
∞
(
n
+
2
)
⋅
(
n
+
1
)
!
+
(
n
+
1
)
!
(
n
+
2
)
⋅
(
n
+
1
)
!
−
(
n
+
1
)
!
=
lim
n
→
∞
(
n
+
2
)
+
1
(
n
+
2
)
−
1
=
lim
n
→
∞
n
+
3
n
+
1
=
1
∴
10
L
=
10
Suggest Corrections
0
Similar questions
Q.
The value of
L
=
lim
n
→
∞
(
(
n
+
1
)
(
n
+
2
)
…
.3
n
n
2
n
)
1
n
is equal to :
Q.
l
i
m
n
→
∞
(
n
+
2
)
!
+
(
n
+
1
)
!
(
n
+
2
)
!
−
(
n
+
1
)
!
is equal to
Q.
A sequence is a function whose domain is the set of natural number. A sequence
s
1
,
s
2
.
.
.
of real numbers is said to have a limit
l
if
lim
n
→
∞
s
n
=
l
. If
l
<
∞
,
then
<
s
n
>
is said to convergent. The following are well known
(i)
lim
n
→
∞
1
n
p
=
0
(
p
>
0
)
(ii)
lim
n
→
∞
x
n
=
0
(
|
x
|
<
1
)
(iii) If
lim
n
→
∞
s
n
=
l
, then
lim
n
→
∞
s
1
+
s
2
+
.
.
.
+
s
n
n
=
l
Let
f
(
x
)
=
−
1
+
|
x
−
1
|
,
g
(
x
)
=
2
−
|
x
+
1
|
then
Q.
if
S
n
=
[
1
1
+
√
n
+
1
2
+
√
n
+
.
.
.
+
1
n
+
√
n
2
]
, then
lim
n
→
∞
S
n
is equal to
Q.
lim
n
→
∞
(
n
2
−
n
+
1
n
2
−
n
−
1
)
n
(
n
−
1
)
is equal to
View More
Join BYJU'S Learning Program
Grade/Exam
1st Grade
2nd Grade
3rd Grade
4th Grade
5th Grade
6th grade
7th grade
8th Grade
9th Grade
10th Grade
11th Grade
12th Grade
Submit
Explore more
Standard Logarithm
Standard XI Mathematics
Join BYJU'S Learning Program
Grade/Exam
1st Grade
2nd Grade
3rd Grade
4th Grade
5th Grade
6th grade
7th grade
8th Grade
9th Grade
10th Grade
11th Grade
12th Grade
Submit
Solve
Textbooks
Question Papers
Install app