If LCM $(P, Q, R)$ $= (P) (Q) (R)$ , then HCF $(P, R) =$

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Solution

The correct option is B $1$
Given, $L C M (P, Q, R) = P \times Q \times R$
This mean, $P, Q, R$ are all prime numbers as LCM of prime numbers is their product.
So, $H C F (P, R)$ will be $= 1$ as HCF of two prime numbers is always $1$

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If LCM (P,Q,R) =(P)(Q)(R), then HCF (P,R)=

The correct option is B 1Given, LCM(P,Q,R)=P×Q×RThis mean, P,Q,R are all prime numbers as LCM of prime numbers is their product.So, HCF(P,R) will be =1 as HCF of two prime numbers is always 1

If LCM $(P, Q, R)$ $= (P) (Q) (R)$ , then HCF $(P, R) =$

The correct option is B $1$
Given, $L C M (P, Q, R) = P \times Q \times R$
This mean, $P, Q, R$ are all prime numbers as LCM of prime numbers is their product.
So, $H C F (P, R)$ will be $= 1$ as HCF of two prime numbers is always $1$