Question

If leap year is selected at random, the probability that it will contain 53 Sundays is equal to:

• A. $\frac{2}{7}$
• B. $\frac{3}{7}$
• C. $\frac{1}{7}$
• D. $None$

Answer 1

The correct option is A $\frac{2}{7}$

In a leap year, we have 366 days of which, there are 52 full weeks and two days more. These two days will be two consecutive days of a week. A leap year will have 53 Sundays if out these two consecutive days of a weak, one is a Sunday.
$\therefore$ S ={(Sunday, Monday), (Monday, Tuesday),
(Thuesday, wednesday) (Wedneday, Thursday),
(Thursday, Friday), (Friday, Saturday), (saturday, Sunday)}.
Total ways = O (S)= 7,
Favourable ways = 2.