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Question

The probability that a non leap year selected at random will contain 53 Sundays is

A
17
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B
27
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C
37
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D
57
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Solution

The correct option is A 17

As we know, a non-leap year has 365 days

365 days =(52×7+1) days

365 days =52 weeks + 1 day

(7 days=1 week)

For 52 weeks, number of Sundays =52

1 remaining day can be Sunday, Monday,Tuesday,Wednesday, Thursday,Friday,Saturday, Sunday.

Total number of possible outcomes =7

Number of favorable outcomes =1

Thus, the probability of getting 53 Sundays

=Number of favorable outcomesTotal number of possible outcomes

=1/7

Therefore, option (a.) is the correct choice.


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