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Question

The probability that a leap year selected at random will contain 53 Sundays, is

A
37
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B
17
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C
0
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D
27
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Solution

The correct option is D 27

A leap year has 366 days or 52 weeks and 2 odd days. The two odd days can be:

{Sunday,Monday},{Monday,Tuesday},{Tuesday,Wednesday},{Wednesday,Thursday},{Thursday,Friday},{Friday,Saturday},{Saturday,Sunday}.

So there are 7 possibilities out of which 2 have a Sunday. So the probability of 53 Sundays is P(E)=27.

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