If $(1 - i) x + (1 + i) y = 1 - 3 i,$ then $(x, y)$ =

(2, - 1)

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(- 2, - 1)

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(- 2, 1)

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(2, 1)

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Solution

The correct option is B $(2, - 1)$
$(1 - i) x + (1 + i) y = 1 - 3 i$
Comparing real part and imaginary part, we get
$x + y = 1$
$x - y = 3$
On adding, $2 x = 4 ⟹ x = 2$
Hence $y = - 1$

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