Question

If ${\left(\frac{3}{5}\right)}^3{\left(\frac{3}{5}\right)}^{-6}={\left(\frac{3}{5}\right)}^{2x-1}$, then x is equal to

• A. -2
• B. 2
• C. -1
• D. 1

Answer 1

Answer: (C)

-1

${\left(\frac{3}{5}\right)}^3{\left(\frac{3}{5}\right)}^{-6}={\left(\frac{3}{5}\right)}^{2x-1}$

= ${\left(\frac{3}{5}\right)}^{3-6}={\left(\frac{3}{5}\right)}^{2x-1}$

= ${\left(\frac{3}{5}\right)}^{-3}={\left(\frac{3}{5}\right)}^{2x-1}$

So, $2x-1=-3$

$2x=-3+1$

$2x=-2$

$x=-1$