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Question

If limxax5a5xa=405, find all possible values of a.

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Solution

Given limxax5a5xa=405....(i)

LHS=limxax5a5xa

=5(a)51

=5a4 It is given that 5a4=405

5a4=405

a4=4055=81

a4=(3)4,a2=9

a=±3

a=3 and a=-3


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