If limx→ax9−a9x−a=limx→5(4+x), find all possible values of a.
Given limx→ax9−a9x−a=limx→5(4+x).....(i)
LHS=limx→ax9−a9x−a
=9(a)9−1=9a8........(ii)
RHS=limx→5(4+x)=4+5=9.......(iii)
Subsituting (ii)and (iii)in (i),
9a8=9
a8=1
⇒a2=1
⇒a=1,a=−1
If limx→ax9−a9x−a=9, find all possible values of a.
If limx→ax3−a3x−a=limx→1x4−1x−1, find all possible values of a.
If limx→ax5−a5x−a=405, find all possible values of a.