If log 2 = 0.3010 and log 3 = 0.4771, the value of log5512 is:
2.870
2.967
3.876
3.912
log5512=log 512log 5 =log29log(102) =9 log 2log 10−log 2 =9×0.30101−0.3010 =2.7090.699 =3.876
If log 2 = 0.3010 and log 3 = 0.4771, find the value of log√24